Answer:
\(k=1.23J\)
Explanation:
1. The equation to calculate the kinetic energy is:
\(k=\frac{mv^{2} }{2}\) (Eq.1)
where, m=mass, v=velocity, k=kinetic energy
2. Find the mass of one mole of water, \(H_{2}O\):
Atomic weight of H = 1\(\frac{g}{mol}\)
Atomic weight of O = 16\(\frac{g}{mol}\)
Molecular weight of \(H_{2}O\) = (2*1) + 16
Molecular weight of \(H_{2}O\) = 18\(\frac{g}{mol}\)
3. Convert the mass of \(H_{2}O\) from g to Kg:
\(18g*\frac{1Kg}{1000g}=0.018Kg\)
3. Replace quantities in Eq.1:
\(k=\frac{0.018g*(11.7\frac{m}{s})^{2}}{2}\)
\(k=1.23J\)
