Point slope form is \(y - y_1 = m(x-x_1)\) in general where
m = slope
(x1,y1) = point the line goes through
In this case, m = 5 is the given slope
(x1,y1) = (1,3) is the given point the line goes through which means
x1 = 1
y1 = 3
So let's plug m = 5, x1 = 1, y1 = 3 into the general equation above to get...
\(y - y_1 = m(x-x_1)\)
\(y - 3 = 5(x-1)\)
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So the final answer is \(y - 3 = 5(x-1)\)
