Explanation:
The given data is as follows.
Volume = 0.25 ml = \(0.25 \times 0.001 L/ml\) = 0.00025 l
mass = \(5.4 \times 10^{-4} g/l\)
Also, it is known that molar mass of stearic acid is 284.48 g/mol.
Therefore, calculate the mass present in 0.00025 l as follows.
\(0.00025 l \times 5.4 \times 10^{-4} g/l\)
= \(0.00135 \times 10^{-4}\)
= 13.5 g
As number of moles is mass divided by molar mass of the substance. Hence, calculate the number of moles of stearic acid as follows.
No. of moles = \(\frac{mass}{\text{molar mass}}\)
= \(\frac{13.5 g}{284.48 g/mol}\)
= 0.047 mol
Thus, we can conclude that there are 0.047 mol of steric acid are contained in the given solution.
