If line r is perpendicular to line q, then the slope of line r is -11/9
The line p passes through the points (-7, -9) and (4, 0)
The slope of the line p is calculated as:
\(m _{p} = \frac{0 - ( - 9)}{4 - ( - 7)}\)
\(m_{p} = \frac{9}{11}\)
Line q is parallel to line p. This means that they have equal slope
\(m_{p} = m_{q} = \frac{9}{11}\)
Line r is perpendicular to line q. This means that the product of their slopes is -1
\(m_{r} = \frac{ - 1}{m_{q}}\)
\(m_{r} = \frac{ - 1}{ \frac{9}{11} }\)
\(m_{r} = \frac{ - 11}{9}\)
Therefore, the slope of line r is -11/9
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