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What is the equation of the graphed line written in standard form?


x – 4y = 4

x + 4y = 4

y = x – 1

y = –x – 1

What is the equation of the graphed line written in standard form? x 4y = 4 x + 4y = 4 y = x 1 y = x 1 class=

Verified Answer :

Setor9

First of all, standard form means it should be this form ax+by=c
The equation for the line is
y= 1/4x-1========>Multiply each term by 4
y (4) = 1/4(4)x-1(4)
4y = 4/4x-4
4y=x-4=========>Subtract x from both sides
4y-x=x-x-4

4y-x=-4 OR X-4Y=4
Your answer is A.

we know that

The equation of the line in standard form is equal to

\(Ax+By=C\)

where

A is a positive integer

B and C are integers

Step 1

Find the slope of the graphed line

we have

\(A(0,-1)\ B(4,0)\)

The slope of the line is equal to

\(m=\frac{y2-y1}{x2-x1}\)

Substitute the values

\(m=\frac{0+1}{4-0}\)

\(m=\frac{1}{4}\)

Step 2

Find the equation of the line in slope-intercept form

the equation of the line in slope-intercept form is equal to

\(y=mx+b\)

where

m is the slope

b is the value of the y-intercept

In this problem we have

\(m=\frac{1}{4}\)

\(b=-1\) ------> see the graph

substitute

\(y=\frac{1}{4}x-1\)

Step 3

Convert to standard form

Multiply by \(4\) both sides

\(4y=x-4\)

\(x-4y=4\)

therefore

the answer is the option

\(x-4y=4\)