don't repost. be patient and we will answer
so
remember some stuff
to find the axis of symmetry of y=ax^2+bx+c
the axis of symmetry is x=-b/(2a)
that is also the x value of the vertex
to get the y value of the vertex, sub the x value of the vertex into the function
and if a is positive, then the parabola opens up and the vertex is a minimum
if a is negative, parabola opens down and vertex is max
so
y=3x^2-6x+4
3 is positive so vertex is a minimum
axis of symmetry is -(-6)/(2*3)=6/6=1
x=1 is axis of symmetry and x value of vertex
sub to find y
y=3(1)^2-6(1)+4
y=3(1)-6+4
y=3-2
y=1
axis of symmetry is x=1
vertex is (1,1)
it is a minimum
the parabola opens up
