Verified Answer :

LammettHash

By the rational root theorem, we have several possible candidates for roots: \(\pm1,\pm2,\pm3,\pm6\)

Plugging each of these options in, you find that \(p(x)=0\) for \(x=1,2,3\). The polynomial remainder theorem states that \(x-c\) is a factor of \(p(x)\) if and only if \(p(c)=0\).

This means

\(p(x)=(x-1)(x-2)(x-3)\)

Related Questions