There are 200 students in the 8th grade class at Alleghany Middle School. Of these students, 8% play basketball and 14% play soccer. Six students play on both teams. What is the probability that a student plays either basketball or soccer?
Answer:
The probability that a student plays either basketball or soccer is 19% or 0.19.
Step-by-step explanation:
Let A be the event that student play basketball and B be the event that student play soccer.
\(P(A)=8\%\)
\(P(B)=14\%\)
It is given that 6 students play on both teams.
\(P(A\cap B)=\frac{6}{200}\times 100=3\%\)
We have to find the probability that a student plays either basketball or soccer.
\(P(A\cup B)=P(A)+P(B)-(A\cap B)\)
\(P(A\cup B)=8\%+14\%-3\%\)
\(P(A\cup B)=19\%\)
Therefore the probability that a student plays either basketball or soccer is 19% or 0.19.
Answer:
19%
Step-by-step explanation:
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