Answer: He did 10198.5 J of work.
Explanation:
As it is given in the problem, A 70.0 kg sailor climbs a 28.3 m rope ladder at an angle of 45.0° with the mast.
Calculate the force.
\(F=mg\)
Here, m is the mass and g is the acceleration due to gravity.
Put m= 70.0 kg and g=9.8 meter per second.
\(F=(70.0)(9.8)\)
\(F=(70.0)(9.8)\)
\(F=686 N\)
Use the formula for the work done.
\(W=Fs\cos \Theta\)
Here, F is the force, s is the displacement and \(\Theta\) is the angle between the force and displacement.
Put F=686 N, s=28.3 m and \(\Theta\)=45.0°.
\(W=(686)(28.3)\cos \(45.0°)\)
\(W=(686)(28.3)\cos \(45.0°)\)
\(W=10198.5 J\)
Therefore, he did 10198.5 J of work.
