The leg of a right triangle is 3 units and the hypotenuse is 11 units. What is the length, in units, of the other leg of the triangle

Verified Answer :

pythagorean theorem (or however it is spelled)

a^2 + b^2 = c^2...where a and b are the legs and c is the hypotenuse

3^2 + b^2 = 11^2
9 + b^2 = 121
b^2 = 121 - 9
b^2 = 112...take the square root of both sides, eliminating the ^2
b = square root of 112
b = 10.58 <=== the other leg of the triangle

The leg of a right triangle is 3 units and the hypotenuse is 11 units then the other leg of the triangle is 10.58 units.

The leg of a right triangle is 3 units and,

The hypotenuse is 11 units.

What is the pythagorean theorem?

\(a^2 + b^2 = c^2\)

Where a and b are the legs and c is the hypotenuse

Therefore plug the given value in the above formula

leg = 3 units and, hypotenuse =11 units

Therefore we get,

\(3^2 + b^2 = 11^2\)

\(9 + b^2 = 121\)

\(b^2 = 121 - 9\)

\(b^2 = 112\)

Take the square root of both sides, eliminating the square.

\(b = \sqrt{112}\)

\(b = 10.58\)

The other leg of the triangle is 10.58 units.

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