The leg of a right triangle is 3 units and the hypotenuse is 11 units. What is the length, in units, of the other leg of the triangle
pythagorean theorem (or however it is spelled)
a^2 + b^2 = c^2...where a and b are the legs and c is the hypotenuse
3^2 + b^2 = 11^2
9 + b^2 = 121
b^2 = 121 - 9
b^2 = 112...take the square root of both sides, eliminating the ^2
b = square root of 112
b = 10.58 <=== the other leg of the triangle
The leg of a right triangle is 3 units and the hypotenuse is 11 units then the other leg of the triangle is 10.58 units.
The leg of a right triangle is 3 units and,
The hypotenuse is 11 units.
\(a^2 + b^2 = c^2\)
Where a and b are the legs and c is the hypotenuse
Therefore plug the given value in the above formula
leg = 3 units and, hypotenuse =11 units
Therefore we get,
\(3^2 + b^2 = 11^2\)
\(9 + b^2 = 121\)
\(b^2 = 121 - 9\)
\(b^2 = 112\)
Take the square root of both sides, eliminating the square.
\(b = \sqrt{112}\)
\(b = 10.58\)
The other leg of the triangle is 10.58 units.
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