What is the width of the path is?
(2x+14)(2x+20)=8324x^2+40x+28x+280=8324x^2+68x+280=8324x^2+68x+280-832=832-8324x^2+68x-552=0(x-6)(4x+92)=0x=6 or -23since distance cannot be negative only the positive answer is possibleSolution: The width of the path is 6 meters