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brieHehshereear brieHehshereear
  • 23-02-2017
  • Mathematics
Answered

Find the equation of the tangent line to the curve y=11xex at the point (0,0). the equation of this tangent line can be written in the form y=mx

Bfind m and

b.

Verified Answer :

LammettHash
LammettHash LammettHash
  • 23-02-2017

\(y=11xe^x\implies y'=11e^x(x+1)\)

When \(x=0\), the slope of the tangent line is \(11e^0(0+1)=11\). The equation of the tangent line in point-slope form is then

\(y-0=11(x-0)\implies y=11x\)

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