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What is the equation of the line, in slope-intercept form, that is perpendicular to the line with the equation y=6x−1 and passes through the point (−6,4)?

y=−6x+10

y=−1/6x−163

y=6x+40

y=−1/6x+3

y=6x+22

Verified Answer :

apologiabiology

perpendicular means has slope that multiplies to -1

y=6x-1
slope=6

6 times what=-1
what=-1/6

so

the equation of a line that passes through the point (x1,y1) and has a slope of m is
y-y1=m(x-x1)
given
point (-6,4) and slope is -1/6

y-4=-1/6(x-(-6))
y-4=-1/6(x+6)
expand
y-4=-1/6x-1
y=-1/6x+3



4th choice

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