The area of a right triangle is 336 cm². the base of the right triangle is 48 cm.what is the length of the hypotenuse of the right triangle?
Area of a triangle=1/2bh
where area is given
336=1/248h
h =336*2/48
h=14 cm
now b=48 cm,h=14 cm
so by phythgorean theorm
(hy)^2=(base)^2+(h)^2
hy= √(196+2304)
Hypotenuse=50cm
The hypotenuse is 50 cm.
In a triangle, one angle is 90 degrees.
Given
The area is 336 square cm
Base is 48
\(\begin{aligned} \rm Area &= \dfrac{1}{2} base * height\\\\336 &= \frac{1}{2} 48* height\\\\Height &= \frac{336}{24}\\Height &= 14\\ \end{aligned}\)
Then by Pythagoras theorem
\(\rm Hypotaneuos^{2} = base^{2} + height^{2} \\Hypotaneuos^{2} = 48^{2} + 14^{2} \\Hypotaneuos^{2} = 2304 +196\\Hypotaneuos^{2} = 2500\\Hypotaneuos = \sqrt{2500} \\Hypotaneuos = 50\)
Thus, the hypotenuse is 50 cm.
More about the right triangle link is given below.
https://brainly.com/question/7894175