In 5 second it reaches maximum height.
According to the question,
- u = 160 ft/s
- g = 32 ft/ s²
We know that,
→ \(s(t) = ut-(\frac{1}{2} )gt^2\)
By substituting the values, we get
→ \(= 160t-16t^2\)
Now,
→ \(\frac{ds}{dt} = 160-32 t\)
\(\frac{ds}{dt} =0\) at maximum height, then
→ \(160-32t=0\)
→ \(32t = 160\)
→ \(t = \frac{160}{32}\)
→ \(= 5 \ sec\)
Thus the above response is right.
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