Answer:
See the explanation.
Explanation:
Hello,
In this case, the overall double displacement undergoing chemical reaction turn out into:
\(Sr(OH)_2+2CH_3COOH-->(CH_3COO)_2Sr+2H_2O\)
The names are:
\(Sr(OH)_2\): strontium hydroxide.
\(CH_3COOH\): acetic acid.
\((CH_3COO)_2Sr\): strontium acetate.
\(H_2O\): water.
Now, the net ionic equation is obtained from the following procedure:
\(Sr^{+2}(aq)+OH^-(aq)+CH_3COOH(aq)-->CH_3COO^-(aq)+H_2O(l)+Sr^{+2}\\OH^-(aq)+CH_3COOH(aq)-->CH_3COO^-(aq)+H_2O(l)\)
In which it is seen that the strontium ion is cancelled as it is completely dissociated unlike the acetate at the left side.
Best regards.
