Now, Laura has \(9\frac{1}{6}\) yard of ribbon
Further Explanation
Given:
Laura bought \(8\frac{3}{10}\) yard of ribbon
She used \(1\frac{2}{5}\) yard to tie a package
She used \(2\frac{1}{3}\) to make a bow
Joe gave her \(4\frac{3}{5}\) yard
Question:
How much ribbon does she have now?
In the right order it would be:
\(\boxed {= 8\frac{3}{10} - 1\frac{2}{5} - 2\frac{1}{3} + 4\frac{3}{5} }\)
but we are going to grouping them for ease:
\(\boxed {= 8\frac{3}{10} + 4\frac{3}{5} - 1\frac{2}{5} + 2\frac{1}{3} }\\\boxed {= 8\frac{3}{10} + 3\frac{1}{5} + 2\frac{1}{3} }\)
they have different denominator, so we are going to find the common denominator for 10, 5 and 3 which is 30
\(\boxed {= 8\frac{9}{30} + 3\frac{6}{30} - 2\frac{10}{30} }\\ \boxed {= 9\frac{5}{30} }\\ \boxed {= 9\frac{1}{6} }\)
So, Laura has \(9\frac{1}{6}\) yard of ribbon now.
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Keyword: mixed fraction, subtraction, improper fraction, part to whole relationship
