Answer:
\(0.85 mol Zn(NO_3)_2\)
Explanation:
we calculate the molecular mass of the compound
\(Zn= 65 g/mol\\N= 14 g/mol\\O= 16 g/mol\)
\(Zn(NO_3)_2= 65+2(14)+ 6(16)=189 g/mol\)
We know that in a 1 mol of \(Zn(NO_3)_2\) there are 189 grams
To calculate how many moles of \(Zn(NO_3)_2\) are in 161.50 grams we apply a simple rule of three
\(189g \longrightarrow 1mol\\161.5g \longrightarrow x \\ x=\frac{(161.5)(1)}{189}\\ x= 0.85 mol\)
\(0.85 mol Zn(NO_3)_2\)
