Factor –8x3 – 2x2 – 12x – 3 by grouping. What is the resulting expression? A. (2x2 – 3)(4x + 1) b. (–2x2 – 3)(–4x + 1) c. (2x2 – 3)(–4x + 1) d. (–2x2 – 3)(4x + 1)

Verified Answer :

it's D
 (–2x2 – 3)(4x + 1)

frika

Consider the polynomial \(-8x^3 - 2x^2 - 12x - 3\). You can group first two terms and second two terms:

\(-8x^3 - 2x^2 - 12x - 3= (-8x^3 - 2x^2 )+(- 12x - 3)\).

Find the common factors in both brackets:

  • in brackets \((-8x^3 - 2x^2 )\) the common factor is \(-2x^2\);
  • in brackets \((- 12x - 3)\) the common factor is \(-3\).

Then rewrite the polynomial as

\(-8x^3 - 2x^2 - 12x - 3= (-8x^3 - 2x^2 )+(- 12x - 3) =-2x^2(4x+1)-3(4x+1)\).

Here you see that expression 4x+1 is common, then

\(-8x^3 - 2x^2 - 12x - 3=-2x^2(4x+1)-3(4x+1)=(4x+1)(-2x^2-3).\).

Answer: correct choice is D.