Answer:
\(v_y=71.25\ m/s\)
Explanation:
Given that,
Speed of an airplane, v = 750 km/hr = 208.33 m/s
An airplane is flying 20.0 degrees north of east, \(\theta=20^{\circ}\)
To find,
Velocity in north direction.
Solution,
Let \(v_y\) is the speed of the airplane to the north. The y component of any motion is given by :
\(v_y=v\ sin\theta\)
\(v_y=208.33\ m/s\ sin(20)\)
\(v_y=71.25\ m/s\)
So, the airplane is moving with a speed of 71.25 m/s to the north direction.
