Answer: The common ratio of the given geometric sequence = 6.
Step-by-step explanation:
We are given the given geometric sequence : {3, 18, 108, ...}
Here the first term = \(a_1=3\)
The second term = \(a_2=ar=18\)
The third term = \(a_3=ar^2=108\)
Then common ratio of the above geometric sequence with n terms is given by:-
\(r=\dfrac{a_{m+1}}{a_m}=\dfrac{108}{3}=\dfrac{18}{3}=6\)
therefore, the common ratio of the given geometric sequence = 6.
