Answer:
The area of the floor is \(908.5\ ft^{2}\)
Step-by-step explanation:
we know that
The area of the floor is equal to the area of rectangle plus the area of triangle
Step 1
Find the area of the rectangle
The area of rectangle is equal to
\(A=LW\)
we have
\(L=38\ ft\)
\(W=20\ ft\)
substitute
\(A=38*20=760\ ft^{2}\)
Step 2
Find the area of triangle
The area of triangle is equal to
\(A=\frac{1}{2}bh\)
we have
\(b=38-5=33\ ft\)
\(h=29-20=9\ ft\)
substitute
\(A=\frac{1}{2}(33)(9)=148.5\ ft^{2}\)
Step 3
Find the area of the floor
\(760\ ft^{2}+148.5\ ft^{2}=908.5\ ft^{2}\)
