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erincK9aylsti erincK9aylsti
  • 22-02-2017
  • Chemistry
Answered

What is the potential at a distance of 5.0 x 10-10 m from a nucleus of charge 50e? question options:?

Verified Answer :

meet3900 meet3900
  • 22-02-2017

electricpotential V=keQ/r
r = 5.010-10 m,
Q = 50e = 501.6010-19
C = 8010-19 C
V=9.0109 Nm2C-2 8010-19 C / 5.010-10

m = 144V

I hope it helped:)

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