If f(x)=log2(x+4), what is f^-1(3)?
\(f\left( x \right) =\log _{ 2 }{ \left( x+4 \right) } \\ \\ \log _{ 2 }{ \left( x+4 \right) } =y\\ \\ { 2 }^{ y }=x+4\)
\(\\ \\ x={ 2 }^{ y }-4\\ \\ \therefore \quad { f }^{ -1 }\left( x \right) ={ 2 }^{ x }-4\\ \\ \therefore \quad { f }^{ -1 }\left( 3 \right) ={ 2 }^{ 3 }-4=4\)
The value of f^-1(3) is 4
The inverse of a function f(x) is the opposite of the function
The function f(x) is given as:
\(f(x) = log_2(x + 4)\)
Express f(x) as y
\(y = log_2(x + 4)\)
Swap the positions of x and y
\(x = log_2(y + 4)\)
Express as exponents
\(2^x = y + 4\)
Make y the subject
\(y = 2^x - 4\)
Express the equations as an inverse function
\(f^{-1}(x) = 2^x - 4\)
Substitute 3 for x in the above equation
\(f^{-1}(3) = 2^3 - 4\)
Evaluate
\(f^{-1}(3) = 4\)
Hence, the value of f^-1(3) is 4
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