Verified Answer :

\(f\left( x \right) =\frac { 1 }{ 2 } \cdot { 3 }^{ x }\\ \\ \frac { 1 }{ 2 } \cdot { 3 }^{ x }=y\)

\(\\ \\ 2\cdot \frac { 1 }{ 2 } \cdot { 3 }^{ x }=2\cdot y\\ \\ { 3 }^{ x }=2y\\ \\ \log _{ 3 }{ \left( 2y \right) } =x\)

\(\\ \\ \therefore \quad { f }^{ -1 }\left( x \right) =\log _{ 3 }{ \left( 2x \right) }\)

\(\\ \\ \therefore \quad { f }^{ -1 }\left( 7 \right) =\log _{ 3 }{ \left( 2\cdot 7 \right) } =\log _{ 3 }{ 14 }\)

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