Can you simplify 7+4(x+5)
pemdasfirst distributedistributive propertya(b+c)=(ab)+(ac)ac=a times cso 4(x+5)=(4x)+(45)=4x+207+4x+20=4x+27
7+4(x+5), expand the brackets by multiplying 4 & x 4 & 57+4x+20, add 7 & 20 together27+4x, Here is the result