The solutions to the equation are -7.7 and -1.3 option (B) is correct.
What is a quadratic equation?
Any equation of the form \(\rm ax^2+bx+c=0\) where x is variable and a, b, and c are any real numbers where a ≠ 0 is called a quadratic equation.
We have a quadratic equation:
\(\rm x^2+9x+10=0\)
Comparing with the standard form of a quadratic equation, we get:
a = 1, b = 9, and c = 10
We know the formula for finding the roots of a quadratic equation:
\(\rm x = \frac{-b\pm\sqrt{b^2-4ac} }{2a}\)
Putting the values of the a, b, and c in the formula, we get:
\(\rm x = \frac{-9\pm\sqrt{9^2-4(1)(10)} }{2\times1}\)
\(\rm x = \frac{-9\pm\sqrt{81-40} }{2}\\\\\rm x = \frac{-9\pm\sqrt{41} }{2}\)
Taking the plus sign first:
\(\rm x = \frac{-9+\sqrt{41} }{2} \Rightarrow -1.298 \approx -1.3\)
Now taking the negative sign:
\(\rm x = \frac{-9-\sqrt{41} }{2} \Rightarrow -7.7015 \approx -7.7\)
Thus, the solutions to the equation are -1.3 and -7.7 option (B) is correct.
Learn more about quadratic equations here:
brainly.com/question/2263981
