Answer:
\(3\pi\)
Step-by-step explanation:
Given the cylinder has radius of 1 and height of 1.
We know that, the surface area of a cylinder is the sum of the area of both the bases and the curved surface.
\(A_{cylinder}=2\pi r^2+2\pi rh\)
putting the values as \(r=1\) and \(h=1\), we get
\(A_{cylinder}=2\pi (1)^2+2\pi (1)(1)=2\pi +2\pi =4\pi\)
Volume of the cylinder will be,
\(V_{cylinder}=\pi r^2h=\pi (1)^2(1)=\pi\)
The difference will be \(4\pi-\pi=3\pi\)
