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A 20-kg child is tossed up into the air by her parent. The child is 2 meters off the ground traveling 5 m/s.


Circle one: KE / GPE / both


Show your work for finding the values of each type of energy the object has

Verified Answer :

Data:
m (mass) = 20 Kg
h (height) = 2 m
s (speed) = 5 m/s
\(K_{E} = ?\) kinetic energy (Joule)
GPE (Gravitational potential energy ) = ? (joule)
Both = KE + GPE = ?
Adopting: g (gravity) = 10 m/s²

Solving: (Kinetic Energy)
\(K_{E} = \frac{m*s^2}{2}\)
\(K_{E} = \frac{20*5^2}{2}\)
\(K_{E} = \frac{20*25}{2}\)
\(K_{E} = \frac{500}{2}\)
\(\boxed{K_{E} = 250\:J}\end{array}}\qquad\quad\checkmark\)

Solving: GPE
\(GPE = m*g*h\)
\(GPE = 20*10*2\)
\(\boxed{GPE = 400\:J}\end{array}}\qquad\quad\checkmark\)

Solving: Both (KE + GPE)
\(Both = K_{E} + GPE\)
\(Both = 250+400\)
\(\boxed{Both = 650\:J}\end{array}}\qquad\quad\checkmark\)