Verified Answer :

SteelersFan

\(\sqrt[n]{x} \sqrt{x} \sqrt{x} x^{2} \\ \\ \\ \\ \\ \int\limits^a_b {x} \, dx \left \{ {{y=2} \atop {x=2}} \right. x_{123}\)

12x^3 - 14x^2 - 40x
-----------------------
        2x - 5
    (2x-5)(6x^2 +8x)
= -------------------------
          2x - 5
=6x^2 + 8x (2x - 5 is canceled out)

answer is C. 6x^2 + 8x 

hope that helps

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