Answer:
\(194\ ft^{2}\)
Step-by-step explanation:
we know that
The area of the figure is equal to the area of the rectangle plus the area of one circle (Remember that the area of two semicircles is equal to the area of one circle)
step 1
Find the area of rectangle
The area of rectangle is equal to
\(A=bh\)
we have
\(b=8\ ft\)
\(h=18\ ft\)
substitute
\(A=8*18=144\ ft^{2}\)
step 2
Find the area of one circle
The area of the circle is equal to
\(A=\pi r^{2}\)
we have
\(r=8/2=4\ ft\)
\(\pi=3.14\)
substitute
\(A=(3.14)(4^{2})=50.24\ ft^{2}\)
step 3
Find the area of the figure
\(144\ ft^{2}+50.24\ ft^{2}=194.24\ ft^{2}\)
Round to the nearest whole number
\(194.24\ ft^{2}=194\ ft^{2}\)
