Suppose you have a normally distributed set of data pertaining to a standardized test. The mean score is 500 and the standard deviation is 100. What is the z-score of 225 point score?

Verified Answer :

\(z=\dfrac{225-500}{100}=-2.75\)

Answer: -2.75

Step-by-step explanation:

Given : We have a normally distributed set of data pertaining to a standardized test.

The mean score is \(\mu=500\)

Standard deviation: \(\sigma=100\)

Let x be a random variable to represent the data values .

The formula for z-score :-

\(z=\dfrac{x-\mu}{\sigma}\)

For x=225, we have

\(\Rightarrow\ z=\dfrac{225-500}{100}=-2.75\)

Hence, the z-score of 225 point score =-2.75