We don't know what \(n\) and \(p\) are, but we can derive the mean and variance with the general parameters using the PMF of the distribution. It's a tedious bit of work, so I'll cut to the chase:
\(\text{mean}=np\)
\(\text{variance}=np(1-p)\)
\(\text{standard deviation}=\sqrt{\text{variance}}=\sqrt{np(1-p)}\)
