Answer: The molarity of sucrose solution is 0.286 M
Explanation:
To calculate the molarity of solution, we use the equation:
\(\text{Molarity of the solution}=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}\)
We are given:
Mass of solute (sucrose) = 171 g
Molar mass of sucrose = 342 g/mol
Volume of solution = 1.75 L
Putting values in above equation, we get:
\(\text{Molarity of solution}=\frac{171g}{342g/mol\times 1.75L}\\\\\text{Molarity of solution}=0.286M\)
Hence, the molarity of sucrose solution is 0.286 M
