Calculus help please! Click the link to see the integral.


\(\int\limits { \frac{cosx}{ \sqrt{sinx} } } \, dx\)

Verified Answer :

Let \(u=\sin x\), then \(\mathrm du=\cos x\,\mathrm dx\). Now

\(\displaystyle\int\frac{\cos x}{\sqrt{\sin x}}\,\mathrm dx=\int\frac{\mathrm du}{\sqrt u}=\int u^{-1/2}\,\mathrm du\)

The power rule for integration gives

\(\displaystyle\int u^{-1/2}\,\mathrm du=2u^{1/2}+C=2\sqrt{\sin x}+C\)