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To 225 mL of a 0.80M solution of KI, a student adds enough water to make 1.0L of a more dilute KI solution. What is the molarity of the new solution? A.180M B. 2.8M C. 0.35M D. 0.18M

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AbhiGhost

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Answer: The correct answer is Option D

Explanation:

To calculate the molarity of the diluted solution, we use the equation:

\(M_1V_1=M_2V_2\)

where,

\(M_1\text{ and }V_1\) are the molarity and volume of the concentrated solution

\(M_2\text{ and }V_2\) are the molarity and volume of diluted solution

We are given:

Conversion factor: 1 L = 1000 mL

\(M_1=0.80M\\V_1=225mL\\M_2=?M\\V_2=1L=1000mL\)

Putting values in above equation, we get:

\(0.80\times 225=M_2\times 1000\\\\M_2=0.18M\)

Hence, the correct answer is Option D

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