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Suppose a cyclist travels 15 kilometers during the first hour. Then the cyclist travels 33 kilometers during the next 2 hours. What is the cyclist's average speed?

Verified Answer :

AL2006


Average speed  =  (total distance)  /  (total time to cover the distance)

                             =  (15 km + 33 km)  /  (1 hr + 2 hrs)

                             =      (48 km)          /    (3 hrs)

                             =                    (48/3)    km/hr

                             =                       16      km/hr .

hamzaahmeds

This question involves the concepts of average speed, time, and distance.

The average speed of the cyclist is "16 km/hr".

The average speed of the cyclist can be defined as the rate of change of distance of the cyclist:

\(v=\frac{D}{T}\\\\\)

where,

  • v = average speed = ?
  • D = Total Distance Travelled = 15 km + 33 km = 48 km
  • T = Total time of travel = 1 hr + 2 hr = 3 hr

Therefore,

\(v=\frac{48\ km}{3\ hr}\)

v = 16 km/hr

Learn more about average speed here:

https://brainly.com/question/862972

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