The acceleration of the cart is 7.14 m/s² and the time of motion of the cart is 0.89s.
The given parameters;
- net force applied on the cart, F = 15 N
- mass of the cart, m = 2.1 kg
- distance traveled by the cart, s = 2.8 m
- initial velocity of the cart, u = 0
The acceleration of the cart when the given force is applied to it is calculated as follows;
F = ma
\(a = \frac{F}{m} \\\\a = \frac{15}{2.1} \\\\a = 7.14 \ m/s^2\)
The time of motion of the cart when it travels 2.8 m is calculated as follows;
s = ut + ¹/₂at²
2.8 = 0 + (0.5 x 7.14)t²
2.8 = 3.57t²
\(t^2 = \frac{2.8}{3.57} \\\\t^2 = 0.784\\\\t = \sqrt{0.784} \\\\t = 0.89 \ s\)
Thus, the acceleration of the cart is 7.14 m/s² and the time of motion of the cart is 0.89s.
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