Answer:0.28975 moles of nitrogen are formed .
Explanation:
\(4KNO_3(s)\rightarrow 2K_2O(s)+2N_2(g)+5O_2(g)\)
Number of moles of \(KNO_3=\frac{\text{Mass of the}KNO_3}{\text{Molar mass of the}KNO_3}=\frac{58.6 g}{101.11 g/mol}=0.5795 moles\)
According to reaction , 4 mol of \(KNO_3\) produces 2 moles of \(N_2\) gas.
Then,0.5795 moles of \(KNO_3\) will produce=\(\frac{2}{4}\times 0.5795\) moles of \(N_2\) gas:
\(\frac{2}{4}\times 0.5795=0.28975 moles\)
0.28975 moles of nitrogen are formed.
