Given right triangle DEF, what is the value of tan(F)?
we know that
In the right triangle DEF
the tangent of the angle F is equal to
\(tan(F)=\frac{opposite\ side\ angle\ F}{adjacent\ side\ angle\ F}=\frac{DE}{EF}\)
substitute the values
\(tan(F)=\frac{40}{9}\)
therefore
the answer is the option
\(\frac{40}{9}\)
Answer: \(\frac{40}{9}\)
Step-by-step explanation:
We know that for any angle x in a triangle ,
\(\tan x=\frac{\text{side opposite to x}}{\text{side adjacent to x}}\)
Now, for the given triangle DEF, the value of tan(F) is given by :-
\(\tan F=\frac{\text{side opposite to F}}{\text{side adjacent to F}}\\\\\Rightarrow\ \tan F=\frac{40}{9}\)
Hence, the value of tan(F) = \(=\frac{40}{9}\)