Answer: \(30.64\times 10^{23}molecules\)
Explanation: According to Avogadro's law, 1 mole of every substance occupies 22.4 Liters at standard temperature and pressure and contains avogadro's number \((6.023\times 10^{23})\) of particles.
22.4 L of oxygen gas\((O_2)\) contains =\(6.023\times 10^{23}\) molecules of oxygen
113.97 L of oxygen gas\((O_2)\) contains =\(\frac{6.023\times 10^{23}}{22.4L}\times 113.97L=30.64\times 10^{23}\)molecules of oxygen
