How many carbon atoms are present in 1.00 mole of methane ch4?
1 mol CH4 = 1 mol C since 1 C in each CH4.
1 mol C 6.0210^23 atoms/mol = 6.02*10^23 atoms C in 1 mol of CH4
One (1.00) mole of methane (\(CH_4\)) would contain \(6.02 \times 10^{23}\) atoms in accordance with Avogadro's law.
Given the following data:
To calculate the number of atoms that are present in 1.00 mole of methane (\(CH_4\)), we would apply Avogadro's law.
Avogadro's law states that equal volumes of all gases such as methane (\(CH_4\)), have the same number of atoms or molecules at the same temperature and pressure.
Note: Avogadro's constant (number) is equal to \(6.02 \times 10^{23}\).
In Science, Avogadro's number is typically used to determine the number of atoms that are contained in a specific mass and mole of a gas sample.
In conclusion, one (1.00) mole of methane (\(CH_4\)) would contain \(6.02 \times 10^{23}\) atoms in accordance with Avogadro's law.
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