Verified Answer :

3x-5y=4------eq1
4x+3y=15-------------eq2

multiply 3 to first eq and 5 to second eq.

9x-15y=12
20x+15y=75

subtract both eqs

29x=87 x=3 so put x in eq 1

3(3)-5y=4
5y=5
y=1

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