Verified Answer :

trishinada63

Use the distance formula. √(x2-x1)^2 + (y2-y1)^2. √(4--6)^2+(3--1)^2. (10)^2 is 100 + (4)^2 is 16. 100+16=116, and square root of 116 is 2√29

apologiabiology

the distance between\((x_1,y_1)\) and \((x_2,y_2)\) is
\(D= \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}\)

so
distance between (-6,-1) and (4,3) is
\(D= \sqrt{(-6-4)^2+(-1-3)^2}\)
\(D= \sqrt{(-10)^2+(-4)^2}\)
\(D= \sqrt{100+16}\)
\(D= \sqrt{116}\)
D=2√29 or aprox 10.7703

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