What value in place of the question mark makes the polynomial below a perfect square trinomial? x^+26x+?
You do 26 / 2, which would equal 13. Then you would do the square of 13, which would equal 169.
Answer: 169
Step-by-step explanation:
A perfect square trinomial is written as \(ax^2+2abx+b^2\), where
first term \(ax^2\)= square of first term of binomial
second term=\(2abx\)=twice the product of both terms of binomial.
and third term \(b^2\)=square of last term of binomial
In the given polynomial \(x^2+26x+?, a=1\)
\(2ab=26\\\Rightarrow2(1)b=26\\\Rightarrow b=13\)
Hence, in place of the question mark makes the given polynomial a perfect square trinomial =\(b^2=13^2=169\)