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lukyo

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Solve the trigonometric equation, assuming that arcs are in degrees:

sin(6m – 8°) = cos(2m)


The cosine of an angle is equal to the sine of its complementary:

•  cos(2m) = sin(90° – 2m)


so the equation becomes

sin(6m – 8°) = sin(90° – 2m)

sin(6m – 8°) – sin(90° – 2m) = 0


Convert that difference into a product by applying this trigonometric identity:

\(\mathsf{sin\,p-sin\,q=2\cdot sin\!\left(\dfrac{p-q}{2}\right)\cdot cos\!\left(\dfrac{p+q}{2}\right)}\)


for  p = 6m – 8°  and  q = 90° – 2m, and that gives you

\(\mathsf{2\cdot sin\!\left[\dfrac{(6m-8\°)-(90\°-2m)}{2}\right]\cdot cos\!\left[\dfrac{(6m-8\°)+(90\°-2m)}{2}\right]=0}\\\\\\ \mathsf{2\cdot sin\!\left[\dfrac{6m-8\°-90\°+2m}{2}\right]\cdot cos\!\left[\dfrac{6m-8\°+90\°-2m}{2}\right]=0}\)


Combine like terms together in brackets:

\(\mathsf{2\cdot sin\!\left[\dfrac{6m+2m-8\°-90\°}{2}\right]\cdot cos\!\left[\dfrac{6m-2m-8\°+90}{2}\right]=0}\\\\\\ \mathsf{2\cdot sin\!\left[\dfrac{8m-98\°}{2}\right]\cdot cos\!\left[\dfrac{4m+82\°}{2}\right]=0}\\\\\\ \mathsf{2\cdot sin\!\left[\dfrac{\diagup\hspace{-7}2\cdot (4m-49\°)}{\diagup\hspace{-7}2}\right]\cdot cos\!\left[\dfrac{\diagup\hspace{-7}2\cdot (2m+41\°)}{\diagup\hspace{-7}2}\right]=0}\\\\\\ \mathsf{\diagup\hspace{-8}2\cdot sin(4m-49\°)\cdot cos(2m+41\°)=0}\)

\(\mathsf{sin(4m-49\°)\cdot cos(2m+41\°)=0}\)


If a product is zero, then one of the factors must be zero:

\(\mathsf{sin(4m-49\°)=0}~~\textsf{ or }~~\mathsf{cos(2m+41\°)}\)


Solving them separately:

•   \(\mathsf{sin(4m-49\°)=0}\)

\(\mathsf{4m-49\°=k_1\cdot 180\°}\\\\ \mathsf{4m=49\°+k_1\cdot 180\°}\)


Divide both sides by  4, and you have

\(\mathsf{m=\dfrac{49\°}{4}+k_1\cdot \dfrac{180\°}{4}}\)

\(\mathsf{m=12.25\°+k_1\cdot 45^\circ}\)          ✔

where  k₁  is an integer.


•   \(\mathsf{cos(2m+41\°)=0}\)

\(\mathsf{2m+41\°=90\°+k_2\cdot 180\°}\\\\ \mathsf{2m=90\°-41\°+k_2\cdot 180\°}\\\\ \mathsf{2m=49\°+k_2\cdot 180\°}\)


Divide both sides by  2, and you have also

\(\mathsf{m=\dfrac{49\°}{2}+k_2\cdot \dfrac{180\°}{2}}\)

\(\mathsf{m=24.5\°+k_2\cdot 90\°}\)          ✔

where  k₂  is an integer.


Solution set:

S = {m ∈ R:  m = 12.25° + k₁ · 45°   or   m = 24.5° + k₂ · 90°,   k₁, k₂ ∈ Z}.


I hope this helps. =)


Tags:  trigonometric trig equation sum difference product transformation formula relation trigonometry