How many joules of heat are required to heat 125 g aluminum from 19.0°C to 95.5°C?
The specific heat of aluminum is 0.902 J/gC. E=mcpdelta T, or
1250.902(95.5-19)= 8630 J
Answer: The amount of heat required is 8625.4 J
Explanation:
To calculate the heat required, we use the equation:
\(q=mc\Delta T\)
where,
q = heat required = ?
m = mass of aluminium = 125 g
c = specific heat capacity of aluminium = 0.902 J/g.°C
\(\Delta T\) = change in temperature = \(T_2-T_1=95.5-19=76.5^oC\)
Putting values in above equation, we get:
\(q=125g\times 0.902J/g.^oC\times 76.5^oC\\\\\q=8625.4J\)
Hence, the amount of heat required is 8625.4 J