Explanation:
The given data is as follows.
\(M_{1}\) = 0.50 M, \(V_{1}\) = 250 mL
\(M_{1}\) = ? , \(V_{1}\) = 840 mL
Therefore, calculate the molarity using the relation as follows.
\(M_{1} \times V_{1}\) = \(M_{2} \times V_{2}\)
0.50 M × 250 mL = \(M_{2}\) × 840 mL
\(M_{2} = \frac{0.50 M \times 250 mL}{840 mL}\)
= 0.148 M
= 0.15 M (approximately)
Thus, we can conclude that the molarity of the resulting solution is 0.15 M.
