Verified Answer :

hbarisk

To get rid of exponential, you need to put ln on the other side.

So, to get 2x you need to write ln 1732

Answer is the first one.

isyllus

Answer:

Logarithm form of \(e^{2x}=1732\) is \(2x=\ln 1732\)

Step-by-step explanation:

Given equation \(e^{2x}=1732\)

We need to write given exponential form into logarithm

using log property to write in logarithm

\(a^m=x\)

\(m\ln a=\ln x\)

\(e^{2x}=1732\)

Apply ln both sides

\(2x\ln e=\ln 1732\)

\(2x=\ln 1732\)                       ∴ln e = 1

Thus, Logarithm form of \(e^{2x}=1732\) is \(2x=\ln 1732\)

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