katiek0193
Answered

in the figure below,

PT = x + 2

TR = y

QT = 2x

and TS = y + 3


(picture attached below)


find the values of x and y in parallelogram PQRS.

Ax = 2, y = 1
Bx = 1, y = 3
Cx = 4, y = 5
Dx = 5, y = 7

thanks in advance! :)

in the figure below, PT = x + 2 TR = y QT = 2x and TS = y + 3 (picture attached below) find the values of x and y in parallelogram PQRS. A. x = 2, y = 1 B. x = class=

Verified Answer :

similar to the last problem 
y = x + 2
y + 3 = 2x 

so we need to find which values fit 

check out  B and D  - its one of those

Answer:

Option D is correct

x = 5 , y = 7

Step-by-step explanation:

Properties of parallelogram:

Diagonal bisects each other.

In other way, we can say that the diagonal intersects each other at half-way point.

As per the given statement:

PT = x + 2

TR = y

QT = 2x   and TS = y + 3

From the given figure:

In parallelogram PQRS:

By properties we have;

PT = TR

QT = TS

Substitute the given values we have;

\(x+2 = y\)              .....[1]

\(2x = y+3\)           .....[2]

Substitute equation [1] into [2] we have;

\(2x = x+2+3\)

⇒2x = x+5

Subtract x from both sides we have;

x = 5

Substitute x = 5 in [1] we have;

5+2 = y

7 = y

or

y= 7

Therefore, the value of x and y are:

x = 5 , y = 7

 

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